\begin{table} \caption{\label{tab:raytau30}Reflectivity $I(\alpha)$, polarization fraction $q(\alpha)$ and polarized intensity $Q(\alpha)$ phase curves for a very deep ($\tau=30$) conservative $(\omega=1)$ Rayleigh scattering atmosphere above a perfectly reflecting Lambert surface (surface albedo $A_{\rm S}=1$). } \small%\centerline { \begin{tabular}{rcrcc} \hline\hline $\alpha$ [$^\circ$] & $I(\alpha)$ & $q(\alpha)$ [\%]& $Q(\alpha)$ & $a(\alpha)$ \\ \hline 2.5 & 0.795 & 0.0 & 0.0000 & \\ 7.5 & 0.785 & 0.4 & 0.0031 & \\ 12.5 & 0.766 & 1.1 & 0.0084 & \\ 17.5 & 0.740 & 2.1 & 0.0155 & \\ 22.5 & 0.708 & 3.4 & 0.0241 & 1.85 \\ 27.5 & 0.671 & 5.1 & 0.0342 & 1.86 \\ 32.5 & 0.630 & 6.9 & 0.0435 & 1.87 \\ 37.5 & 0.587 & 9.1 & 0.0534 & 1.89 \\ 42.5 & 0.542 & 11.4 & 0.0618 & 1.91 \\ 47.5 & 0.497 & 13.9 & 0.0691 & 1.94 \\ 52.5 & 0.453 & 16.6 & 0.0752 & 1.98 \\ 57.5 & 0.410 & 19.3 & 0.0791 & 2.03 \\ 62.5 & 0.368 & 22.0 & 0.0810 & 2.08 \\ 67.5 & 0.329 & 24.6 & 0.0809 & 2.14 \\ 72.5 & 0.292 & 27.0 & 0.0788 & 2.21 \\ 77.5 & 0.259 & 29.1 & 0.0754 & 2.29 \\ 82.5 & 0.228 & 30.7 & 0.0700 & 2.39 \\ 87.5 & 0.199 & 31.9 & 0.0635 & 2.49 \\ 92.5 & 0.174 & 32.5 & 0.0566 & 2.62 \\ 97.5 & 0.150 & 32.5 & 0.0488 & 2.77 \\ 102.5 & 0.130 & 31.8 & 0.0413 & 2.95 \\ 107.5 & 0.111 & 30.5 & 0.0339 & 3.16 \\ 112.5 & 0.094 & 28.6 & 0.0269 & 3.42 \\ 117.5 & 0.079 & 26.2 & 0.0207 & 3.76 \\ 122.5 & 0.066 & 23.4 & 0.0154 & \\ 127.5 & 0.054 & 20.3 & 0.0110 & \\ 132.5 & 0.043 & 17.0 & 0.0073 & \\ 137.5 & 0.033 & 13.7 & 0.0045 & \\ 142.5 & 0.025 & 10.4 & 0.0026 & \\ 147.5 & 0.018 & 7.3 & 0.0013 & \\ 152.5 & 0.013 & 4.4 & 0.0006 & \\ 157.5 & 0.008 & 2.0 & 0.0002 & \\ 162.5 & 0.005 & 0.0 & 0.0000 & \\ 167.5 & 0.002 & -1.4 & 0.0000 & \\ 172.5 & 0.001 & -1.9 & 0.0000 & \\ 177.5 & 0.000 & & & \\ \hline \end{tabular}} \medskip This model approximates well a conservative, semi-infinite Rayleigh scattering atmosphere. Additionally the fit parameter $a(\alpha)$ for the parametrization of the polarized intensity $Q(\alpha)$ (Eq.~(\ref{eq:Qfit})) is given for relevant phase angles.\protect\\ The statistical error of the Monte Carlo calculation for $I(\alpha)$ is smaller than 0.001 for all $\alpha$. The uncertainty of the polarization fraction is less than 0.1\% for phase angles between 5 and 165 degrees. Extrapolating the intensity $I$ towards $\alpha=0^\circ$ with a quadratic least-squares fit to the first four points ($\alpha = 2.5^\circ,\ldots, 17.5^\circ$) yields a value $I(0^\circ) = 0.7970$. This agrees with the exact solution $I(0^\circ)=0.7975$ from Prather (\cite{prather74}) to the third digit. \end{table}