Table 3
Gaussian fits to the HCN v2 = 1f emission in the two nuclei.
| Line | Rest freq. | Fita | v0 − vsys b | v0 − vN c | Δv1/2 | S 0 | ∫ Sδv | L vib |
d
|
| (GHz) | km s-1 | km s-1 | km s-1 | mJy | Jy km s-1 | 103L⊙ | 10-8 | ||
|
|
|||||||||
| Western nucleus | |||||||||
| HCN J = 3−2,v2 = 1f | 267.199 | double | –33 (4) | –38 | 354 (9) | 90 | 33.8 (0.8) | 58 | 9.2 |
| subtract | 24 (4) | 19 | 296 (10) | 67 | 21.2 (0.6) | 36 | 5.7 | ||
| HCN J = 4−3,v2 = 1f | 356.255 | double | –57 (5) | –63 | 424 (10) | 148 | 67.4 (1.5) | 154 | 24.4 |
| subtract | 14 (11) | 9 | 353 (33) | 112 | 42 (3) | 96 | 15.2 | ||
| Eastern nucleus | |||||||||
| HCN J = 3−2,v2 = 1f | 267.199 | double | 120 (10) | 3 | 220 (30) | 23 | 5.6 (0.5) | 10 | 20.0 |
| subtract | 140 (2) | 23 | 179 (5) | 24 | 4.6 (0.1) | 8 | 16.0 | ||
| HCN J = 4−3,v2 = 1f | 356.255 | double | 132 (2) | 15 | 242 (4) | 43 | 11.2 (0.2) | 26 | 51.9 |
| subtract | 143 (2) | 26 | 209 (5) | 45 | 10.0 (0.1) | 23 | 45.9 | ||
Notes.Results from the Gaussian fit to the HCN v2 = 1f transitions.
Fit procedure: (double) Simultaneous double Gaussian fit to high-velocity HCO+v = 0 and HCN v2 = 1f features; (subtract) Fit to v2 = 1f after HCN emission scaled down to the HCO+ intensity is subtracted (see Sect. 3.3 for details.).
Central velocity of the Gaussian profile with respect to the systemic velocity of the entire system.
Velocity with respect to the individual velocities, VEN and VWN, derived for each nucleus (Sect. 3.2.3).
Assuming log(L) = 11.8 and 10.7 L⊙ for the western and eastern nuclei, respectively (Wilson et al. 2014).
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