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Table D.1

Abundances with respect to total hydrogen nuclei (N(X)/NH, in units of 10−10).

Species Horseheada Orion Barb
PDR Dense core PDR
H2CO 3.40.5+0.5Mathematical equation: $\[3.4_{-0.5}^{+0.5}\]$ 3.00.3+0.4Mathematical equation: $\[3.0_{-0.3}^{+0.4}\]$ 9.0
CH3OH 0.40.3+0.7Mathematical equation: $\[0.4_{-0.3}^{+0.7}\]$ 1.80.3+0.3Mathematical equation: $\[1.8_{-0.3}^{+0.3}\]$ 5.0
CH2CO 4.70.3+0.3Mathematical equation: $\[4.7_{-0.3}^{+0.3}\]$ 1.40.1+0.1Mathematical equation: $\[1.4_{-0.1}^{+0.1}\]$ 0.9
CH3CHO 3.90.1+0.2Mathematical equation: $\[3.9_{-0.1}^{+0.2}\]$ 0.90.1+0.1Mathematical equation: $\[0.9_{-0.1}^{+0.1}\]$ 0.8
CH3CN 1.30.1+0.1Mathematical equation: $\[1.3_{-0.1}^{+0.1}\]$ 0.20.1+0.1Mathematical equation: $\[0.2_{-0.1}^{+0.1}\]$ 0.2
HC3N 0.30.1+0.1Mathematical equation: $\[0.3_{-0.1}^{+0.1}\]$ 0.30.1+0.1Mathematical equation: $\[0.3_{-0.1}^{+0.1}\]$ 0.1
HNCO 2.50.1+0.2Mathematical equation: $\[2.5_{-0.1}^{+0.2}\]$ 0.80.1+0.1Mathematical equation: $\[0.8_{-0.1}^{+0.1}\]$ 0.2

Notes. The total hydrogen nuclei column density is estimated as NH = N(X)/(N(H) + 2N(H2)).

(a)This work. Abundances calculated using NH = 3.8 × 1022 cm−2 (PDR) and NH = 6.4 × 1022 cm−2 (dense core).

(b)Values from Cuadrado et al. (2017). Abundances calculated using NH = 6.3 × 1022 cm−2.

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