Simulation of proton radiolysis of H2O and O2 ices with the Nautilus code

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Volume 708 (April 2026)

A&A, 708 (2026) A237

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Table 4

Reaction network considered here, based on Table 7 of Shingledecker et al. (2017).

Reaction	E_A (K)	f_br
O + O ⟶ $O_{2}^{}$ $Mathematical equation: $\[\mathrm{O}_2^\]$$	0	1.0
O + O₂ ⟶ $O_{3}^{}$ $Mathematical equation: $\[\mathrm{O}_3^\]$$	300^a	1.0
O + O₃ ⟶ 2O₂	2060	1.0
O₃ + O₃ ⟶ 3O₂	9310	1.0
O* + O ⟶ 2O	0	0.5
O* + O ⟶ $O_{2}^{}$ $Mathematical equation: $\[\mathrm{O}_2^\]$$	0	0.5
O* + O₂ ⟶ O + O₂	0	0.9^a
O* + O₂ ⟶ $O_{3}^{}$ $Mathematical equation: $\[\mathrm{O}_3^\]$$	0	0.05^a
O* + O₃ ⟶ 2O₂	0	1.0
$O_{2}^{}$ $Mathematical equation: $\[\mathrm{O}_2^\]$$ + O ⟶ O + O₂	0	0.333^b
$O_{2}^{}$ $Mathematical equation: $\[\mathrm{O}_2^\]$$ + O ⟶ $O_{3}^{}$ $Mathematical equation: $\[\mathrm{O}_3^\]$$	0	0.333^b
$O_{2}^{}$ $Mathematical equation: $\[\mathrm{O}_2^\]$$ + O₂ ⟶ 2O₂	0	1.0
$O_{2}^{}$ $Mathematical equation: $\[\mathrm{O}_2^\]$$ + O₃ ⟶ 2O₂ + O	0	1.0
$O_{3}^{}$ $Mathematical equation: $\[\mathrm{O}_3^\]$$ + O ⟶ 2O₂	0	1.0
$O_{3}^{}$ $Mathematical equation: $\[\mathrm{O}_3^\]$$ + O₂ ⟶ 2O₂ + O	0	1.0
$O_{3}^{}$ $Mathematical equation: $\[\mathrm{O}_3^\]$$ + O₃ ⟶ 3O₂	0	1.0

Notes. a: Benderskii & Wight (1996). b: We set the branching ratios of the reactions involving O* and O₂ to 0.05, 0.9, and 0.05 for the formation of O₃ (in the suprathermal version of Table 3), O + O₂, and $O_{3}^{*}$ $Mathematical equation: $\[\mathrm{O}_3^*\]$$ , respectively. c: We set the branching ratios of these two reactions to 0.333 because reactions in the suprathermal version of Table 3 share the same reactants.

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